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(A) Using the combined gas law,$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$,we can express the ratio of volumes as $\frac{V_2}{V_1} = \frac{P_1 T_2}{P_

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Volume will become greater by a factor of $1.6$.

Vedclass · Answer

(A) Using the combined gas law,$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$,we can express the ratio of volumes as $\frac{V_2}{V_1} = \frac{P_1 T_2}{P_2 T_1}$.Given initial conditions: $T_1 = 15 + 273 = 288 \ K$ and $P_1 = 1.5 \ bar$.Given final conditions: $T_2 = 25 + 273 = 298 \ K$ and $P_2 = 1.0 \ bar$.Substituting the values: $\frac{V_2}{V_1} = \frac{1.5 	imes 298}{1.0 	imes 288} = \frac{447}{288} \approx 1.552$.Rounding to one decimal place,the volume increases by a factor of $1.6$.

$A$ bubble of air is underwater at temperature $15^\circ C$ and the pressure $1.5 \ bar$. If the bubble rises to the surface where the temperature is $25^\circ C$ and the pressure is $1.0 \ bar$,what will happen to the volume of the bubble?

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