A bucket tied at the end of a 1.6, m long str | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For the water not to spill at the highest point of a vertical circle,the gravitational force must provide the necessary centripetal force.At the h

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) For the water not to spill at the highest point of a vertical circle,the gravitational force must provide the necessary centripetal force.At the highest point,the condition for the minimum speed $V$ is given by:$\frac{mV^2}{r} = mg$Where $m$ is the mass of the water,$V$ is the velocity,$r$ is the radius of the circle $(1.6\, m)$,and $g$ is the acceleration due to gravity $(10\, m/sec^2)$.Canceling $m$ from both sides,we get:$V^2 = rg$$V = \sqrt{rg}$Substituting the given values:$V = \sqrt{1.6 	imes 10} = \sqrt{16} = 4\, m/sec$.Thus,the minimum speed required is $4\, m/sec$.

$A$ bucket tied at the end of a $1.6\, m$ long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill,when the bucket is at the highest position? (Take $g = 10\, m/sec^2$)

Similar Questions

Which of the following is a method of plant tissue culture?

Four positive point charges $+q$ are kept at the four corners of a square of side $l$. The net electric field at the mid-point of any one side of the square is (Take,$\frac{1}{4 \pi \varepsilon_0}=k$)

For a reversible reaction $A \rightleftharpoons B$,which one of the following statements is wrong from the given energy profile diagram?

$A$ rocket with a lift-off mass $2 \times 10^4 \ kg$ is blasted upwards with an initial acceleration of $5 \ m \ s^{-2}$. The initial thrust of the blast is (Take $g = 10 \ m \ s^{-2}$)

If $Alpha$,$Beta$,and $\Gamma$ rays carry the same momentum,which has the longest wavelength?

Vedclass Test Series

Exam Paper Generator

Online Exam Module