(D) The formula for the maximum height $(H_{\max})$ attained by a projectile is given by: $H_{\max} = \frac{u^2 \sin^2 \theta}{2g}$ Given: Initial vel

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(D) The formula for the maximum height $(H_{\max})$ attained by a projectile is given by: $H_{\max} = \frac{u^2 \sin^2 \theta}{2g}$ Given: Initial velocity $(u)$ = $280\,m/s$ Angle of projection $(\theta)$ = $30^{\circ}$ Acceleration due to gravity $(g)$ = $9.8\,m/s^2$ Substituting the values into the formula: $H_{\max} = \frac{(280)^2 \times (\sin 30^{\circ})^2}{2 \times 9.8}$ $H_{\max} = \frac{78400 \times (0.5)^2}{19.6}$ $H_{\max} = \frac{78400 \times 0.25}{19.6}$ $H_{\max} = \frac{19600}{19.6}$ $H_{\max} = 1000\,m$

Class 11 Physics 3-2.Motion in Plane Horizontal Projectile Motion

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$A$ bullet is fired from a gun at the speed of $280\,m/s$ in the direction $30^{\circ}$ above the horizontal. The maximum height attained by the bullet is $........\,m$ $\left(g=9.8\,m/s^2, \sin 30^{\circ}=0.5\right):-$

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$3000$
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$2800$
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$2000$
D
$1000$

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$A$ bullet is fired from a gun at the speed of $280\,m/s$ in the direction $30^{\circ}$ above the horizontal. The maximum height attained by the bullet is $........\,m$ $\left(g=9.8\,m/s^2, \sin 30^{\circ}=0.5\right):-$

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Two projectiles are projected at $30^{\circ}$ and $60^{\circ}$ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

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