A bullet of mass 10, g is fired from a rifle. | vedclass

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Question

(A) Given:Mass of the bullet $(m) = 10\, g = 0.01\, kg$Initial velocity of the bullet $(u) = 0\, m s^{-1}$Final velocity of the bullet $(v) = 300\, m

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$1000$

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(A) Given:Mass of the bullet $(m) = 10\, g = 0.01\, kg$Initial velocity of the bullet $(u) = 0\, m s^{-1}$Final velocity of the bullet $(v) = 300\, m s^{-1}$Time taken $(t) = 0.003\, s$Step $1$: Calculate the acceleration $(a)$ of the bullet using the formula $a = \frac{v - u}{t}$.$a = \frac{300 - 0}{0.003} = \frac{300}{0.003} = 100,000\, m s^{-2}$.Step $2$: Calculate the force $(F)$ exerted on the bullet using Newton's second law of motion,$F = m 	imes a$.$F = 0.01\, kg 	imes 100,000\, m s^{-2} = 1000\, N$.Therefore,the force exerted on the bullet by the rifle is $1000\, N$.

$A$ bullet of mass $10\, g$ is fired from a rifle. The bullet takes $0.003\, s$ to move through its barrel and leaves with a velocity of $300\, m s^{-1}$. What is the force exerted on the bullet by the rifle (in $, N$)?

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