A bullet of mass 40 ,g is fired from a gun of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the law of conservation of linear momentum,the total momentum of the system before firing is equal to the total momentum after firing

Vedclass · Accepted Answer

$1.6 \,m/s$ opposite to the direction of the bullet

Vedclass · Answer

(B) According to the law of conservation of linear momentum,the total momentum of the system before firing is equal to the total momentum after firing.Initial momentum $(P_i)$ = $0$ (since both are at rest).Final momentum $(P_f)$ = $m_b v_b + m_g v_g$,where $m_b = 40 \,g = 0.04 \,kg$,$v_b = 400 \,m/s$,$m_g = 10 \,kg$,and $v_g$ is the recoil velocity.$P_i = P_f$$0 = (0.04 \,kg 	imes 400 \,m/s) + (10 \,kg 	imes v_g)$$0 = 16 + 10 v_g$$10 v_g = -16$$v_g = -1.6 \,m/s$.The negative sign indicates that the recoil velocity is in the direction opposite to the motion of the bullet.

$A$ bullet of mass $40 \,g$ is fired from a gun of mass $10 \,kg$. If the velocity of the bullet is $400 \,m/s$,then the recoil velocity of the gun will be ..........

Similar Questions

$A$ body at rest breaks up into $3$ parts. If $2$ parts having equal masses $m$ fly off perpendicularly to each other,each with a velocity of $12 \, m/s$,then the velocity of the third part,which has $3$ times the mass of each part,is:

Two persons of mass $m_1$ and $m_2$ are standing at the two ends $A$ and $B$ respectively,of a trolley of mass $M$ as shown. When only the person standing at $B$ jumps from the trolley towards the right while the person at $A$ keeps standing,then

$A$ bomb of $12 \, kg$ explodes into two pieces of masses $4 \, kg$ and $8 \, kg$. The velocity of the $8 \, kg$ mass is $6 \, m/s$. The kinetic energy of the other mass is ............. $J$.

The momentum of a system is conserved:

Vedclass Test Series

Exam Paper Generator

Online Exam Module