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(C) Given:Diameter of the base $= 40 \, cm$Radius $(r) = \frac{40}{2} \, cm = 20 \, cm = 0.2 \, m$Height $(h) = 1 \, m$Slant height $(l) = \sqrt{r^2 +

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$Rs. 384.34$

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(C) Given:Diameter of the base $= 40 \, cm$Radius $(r) = \frac{40}{2} \, cm = 20 \, cm = 0.2 \, m$Height $(h) = 1 \, m$Slant height $(l) = \sqrt{r^2 + h^2} = \sqrt{(0.2)^2 + (1)^2} \, m = \sqrt{0.04 + 1} \, m = \sqrt{1.04} \, m = 1.02 \, m$Curved surface area of one cone $= \pi r l = 3.14 	imes 0.2 	imes 1.02 \, m^2$Curved surface area of $50$ cones $= 50 	imes 3.14 	imes 0.2 	imes 1.02 \, m^2$$= 50 	imes 0.2 	imes 3.14 	imes 1.02 \, m^2 = 10 	imes 3.14 	imes 1.02 \, m^2 = 32.028 \, m^2$Cost of painting $= 	ext{Total Area} 	imes 	ext{Rate} = 32.028 	imes 12 = Rs. 384.336$Rounding to two decimal places,the cost is $Rs. 384.34$.

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