A can finish a work in 24 days,B in 9 days an | vedclass

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(C) Work done by $B$ in $1$ day $= \frac{1}{9}$ and by $C$ in $1$ day $= \frac{1}{12}$.Work done by $(B + C)$ in $1$ day $= \frac{1}{9} + \frac{1}{12}

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$10$

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(C) Work done by $B$ in $1$ day $= \frac{1}{9}$ and by $C$ in $1$ day $= \frac{1}{12}$.Work done by $(B + C)$ in $1$ day $= \frac{1}{9} + \frac{1}{12} = \frac{4 + 3}{36} = \frac{7}{36}$.Work done by $(B + C)$ in $3$ days $= 3 	imes \frac{7}{36} = \frac{7}{12}$.Remaining work $= 1 - \frac{7}{12} = \frac{5}{12}$.$A$ can finish the whole work in $24$ days,so $A$ does $\frac{1}{24}$ of the work in $1$ day.Time taken by $A$ to complete the remaining work $= \frac{5/12}{1/24} = \frac{5}{12} 	imes 24 = 10$ days.

$A$ can finish a work in $24$ days,$B$ in $9$ days and $C$ in $12$ days. $B$ and $C$ start the work but are forced to leave after $3$ days. The remaining work was done by $A$ in (in days):

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