$A$ cannon on a level plane is aimed at an angle $\theta$ above the horizontal and a shell is fired with a muzzle velocity $v_0$ towards a vertical cliff a distance $D$ away. Then the height from the bottom at which the shell strikes the side walls of the cliff is

  • A
    $D\sin \theta - \frac{gD^2}{2v_0^2\sin^2 \theta}$
  • B
    $D\cos \theta - \frac{gD^2}{2v_0^2\cos^2 \theta}$
  • C
    $D\tan \theta - \frac{gD^2}{2v_0^2\cos^2 \theta}$
  • D
    $D\tan \theta - \frac{gD^2}{2v_0^2\sin^2 \theta}$

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