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(B) When a capacitor is charged and then disconnected from the battery,the charge $Q$ on the plates remains constant.When a dielectric slab of dielect

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decrease in the potential difference across the plates and reduction in the stored energy but no change in the charge on the plates

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(B) When a capacitor is charged and then disconnected from the battery,the charge $Q$ on the plates remains constant.When a dielectric slab of dielectric constant $K$ is introduced between the plates,the capacitance increases to $C' = KC$.Since $Q$ is constant,the new potential difference $V' = \frac{Q}{C'} = \frac{Q}{KC} = \frac{V}{K}$,which means the potential difference decreases.The stored energy $U = \frac{Q^2}{2C}$ becomes $U' = \frac{Q^2}{2C'} = \frac{Q^2}{2KC} = \frac{U}{K}$,which means the stored energy decreases.Therefore,the potential difference and stored energy decrease,while the charge remains unchanged.

$A$ capacitor is charged by using a battery which is then disconnected. $A$ dielectric slab is introduced between the plates which results in

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