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(B) The energy stored in a capacitor is given by $U = \frac{1}{2} C V^2$.When the capacitor discharges through the coil,this energy is converted into

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$500 \,\mu F$

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(B) The energy stored in a capacitor is given by $U = \frac{1}{2} C V^2$.When the capacitor discharges through the coil,this energy is converted into heat,which raises the temperature of the block.The heat gained by the block is given by $Q = m s \Delta T$,where $m$ is the mass,$s$ is the specific heat capacity,and $\Delta T$ is the change in temperature.Equating the energy stored to the heat gained: $\frac{1}{2} C V^2 = m s \Delta T$.Given: $V = 200 \,V$,$m = 0.1 \,kg$,$s = 2.5 	imes 10^2 \,J/(kg \cdot K)$,and $\Delta T = 0.4 \,K$.Substituting the values: $\frac{1}{2} 	imes C 	imes (200)^2 = 0.1 	imes 2.5 	imes 10^2 	imes 0.4$.$\frac{1}{2} 	imes C 	imes 40000 = 10$.$20000 	imes C = 10$.$C = \frac{10}{20000} = \frac{1}{2000} \,F$.$C = 0.0005 \,F = 500 	imes 10^{-6} \,F = 500 \,\mu F$.

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