A capillary tube is immersed vertically in wa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The height of the water column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{r ho g}$,where $T$ is surface tension,$	h

Vedclass · Accepted Answer

$\left( 1 - \frac{d}{R} \right)$

Vedclass · Answer

(A) The height of the water column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{r ho g}$,where $T$ is surface tension,$	heta$ is the contact angle,$r$ is the radius of the tube,$ho$ is the density of water,and $g$ is the acceleration due to gravity.Since $T, 	heta, r,$ and $ho$ are constants,the height $h$ is inversely proportional to $g$,i.e.,$h \propto \frac{1}{g}$.At the surface of the earth,the height is $x = \frac{k}{g}$,where $k = \frac{2T \cos 	heta}{r ho}$.At a depth $d$ inside a mine,the acceleration due to gravity becomes $g' = g \left( 1 - \frac{d}{R} ight)$.The new height is $y = \frac{k}{g'} = \frac{k}{g \left( 1 - \frac{d}{R} ight)}$.Therefore,the ratio $\frac{x}{y} = \frac{k/g}{k / [g(1 - d/R)]} = 1 - \frac{d}{R}$.

$A$ capillary tube is immersed vertically in water and the height of the water column is $x$. When this arrangement is taken into a mine of depth $d$,the height of the water column is $y$. If $R$ is the radius of earth,the ratio $\frac{x}{y}$ is

Similar Questions

If the diameter of a capillary tube is doubled,then the height of the liquid that will rise is

Water rises up to height $x$ in a capillary tube immersed vertically in water. When the whole arrangement is taken to a depth $d$ in a mine,the water level rises up to height $Y$. If $R$ is the radius of the earth,then the ratio $Y:x$ is

Wax is coated on the inner wall of a capillary tube and the tube is then dipped in water. Then,compared to the unwaxed capillary,the angle of contact $\theta$ and the height $h$ up to which water rises change. These changes are:

The maximum length of a water column that can stay without falling in a vertically held capillary tube of diameter $1 \ mm$ and open at both ends is (Acceleration due to gravity $= 10 \ ms^{-2}$ and surface tension of water $= 0.07 \ Nm^{-1}$) (in $cm$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module