$A$ capillary tube of radius $r$ is immersed in water and water rises in it to a height $h$. The mass of the water in the capillary is $5 \, g$. Another capillary tube of radius $2r$ is immersed in water. The mass of water that will rise in this tube is $........ \, g$.

The radius of a capillary tube is $2 \times 10^{-3} \ m$. If a liquid of weight $6.28 \times 10^{-4} \ N$ can be supported in the capillary,what is the surface tension of the liquid?

$A$ vertical capillary tube is filled with water up to the top after closing its lower end with a finger. If the finger is removed,we shall observe that: ($T = 70 \,\, dyne/cm$,radius of capillary $r = 1 \,\, mm$ and $g = 980 \,\, cm/sec^2$)

Water rises to a height of $20 \,mm$ in a capillary tube of cross-sectional area $A$. If the area of cross-section of the tube is made $\frac{A}{4}$, then water will rise to a height of (in $\,cm$)

If we dip capillary tubes of different radii $r_n$ in water and the water rises to different heights $h_n$ in them, then $(n = 1, 2, 3, ...)$

When one end of a capillary tube is dipped in water,the height of water column is $h$. The upward force of $105 \text{ dyne}$ due to surface tension is balanced by the force due to the weight of water column. The inner circumference of the capillary tube is (Surface tension of water $= 7 \times 10^{-2} \text{ N/m}$) (in $\text{ cm}$)