$A$ capillary tube of radius $R$ is immersed in water and water rises in it to a height $H$. The mass of water in the capillary tube is $M$. If the radius of the tube is halved,the mass of water that will rise in the capillary tube will now be

  • A
    $M$
  • B
    $M/2$
  • C
    $2M$
  • D
    $4M$

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