$A$ car has two wipers which do not overlap. Each wiper has a blade of length $25 \, cm$ sweeping through an angle of $115^{\circ}.$ Find the total area cleaned at each sweep of the blades. [use $\pi=\frac{22}{7}$]

(N/A) It can be observed that each blade of the wiper sweeps an area of a sector of $115^{\circ}$ in a circle of radius $r = 25 \, cm$.
The area of a sector of a circle with angle $\theta$ and radius $r$ is given by the formula: $\text{Area} = \frac{\theta}{360^{\circ}} \times \pi r^{2}$.
Area of one sector $= \frac{115^{\circ}}{360^{\circ}} \times \frac{22}{7} \times (25)^{2}$
$= \frac{23}{72} \times \frac{22}{7} \times 625$
$= \frac{23 \times 11 \times 625}{36 \times 7} = \frac{158125}{252} \, cm^{2}$.
Since there are two wipers,the total area cleaned by both blades is:
Total Area $= 2 \times \left( \frac{158125}{252} \right)$
$= \frac{158125}{126} \, cm^{2} \approx 1254.96 \, cm^{2}$.