A car with a vertical windshield moves in a r | vedclass

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(A) First,convert the speed of the car from $km/h$ to $m/s$:$v_m = 40 	imes \frac{5}{18} = \frac{200}{18} = \frac{100}{9} \, m/s$.The velocity of the

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$	an^{-1} \left(\frac{5}{9}ight)$

Vedclass · Answer

(A) First,convert the speed of the car from $km/h$ to $m/s$:$v_m = 40 	imes \frac{5}{18} = \frac{200}{18} = \frac{100}{9} \, m/s$.The velocity of the rain is $v_r = 20 \, m/s$ (vertically downwards).The relative velocity of the rain with respect to the car is the vector sum of the velocity of the rain and the negative velocity of the car.The angle $	heta$ with the vertical at which the rain strikes the windshield is given by:$	an 	heta = \frac{v_m}{v_r}$Substituting the values:$	an 	heta = \frac{100/9}{20} = \frac{100}{9 	imes 20} = \frac{5}{9}$.Therefore,$	heta = 	an^{-1} \left(\frac{5}{9}ight)$.

$A$ car with a vertical windshield moves in a rainstorm at a speed of $40 \, km/h$. The raindrops fall vertically with a constant speed of $20 \, m/s$. The angle at which the raindrops strike the windshield is .........

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