A Carnot engine,having an efficiency of eta = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The efficiency $(\eta)$ of a Carnot engine and the coefficient of performance $(\beta)$ of a refrigerator are related as:$\beta = \frac{1 - \eta}{

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(C) The efficiency $(\eta)$ of a Carnot engine and the coefficient of performance $(\beta)$ of a refrigerator are related as:$\beta = \frac{1 - \eta}{\eta}$Given $\eta = 1/10$,we calculate the coefficient of performance:$\beta = \frac{1 - 1/10}{1/10} = \frac{9/10}{1/10} = 9$The coefficient of performance $(\beta)$ is also defined as the ratio of heat absorbed from the cold reservoir $(Q_2)$ to the work done $(W)$ on the system:$\beta = \frac{Q_2}{W}$Given $W = 10 \ J$ and $\beta = 9$,we have:$9 = \frac{Q_2}{10 \ J}$$Q_2 = 9 	imes 10 \ J = 90 \ J$Therefore,the energy absorbed from the reservoir at a lower temperature is $90 \ J$.

$A$ Carnot engine,having an efficiency of $\eta = 1/10$ as a heat engine,is used as a refrigerator. If the work done on the system is $10 \ J$,the amount of energy absorbed from the reservoir at a lower temperature is ....... $J$.

Similar Questions

Assertion $(A)$: $A$ room can be cooled by opening the door of a refrigerator in it.
Reason $(R)$: Heat always flows from a body at higher temperature to a body at lower temperature.

$A$ refrigerator with a coefficient of performance $0.25$ releases $250 \, J$ of heat to a hot reservoir. The work done on the working substance is

$A$ refrigerator of coefficient of performance $5$ that extracts heat from the cooling compartment at the rate of $250 \ J$ per cycle is placed in a room. The heat released per cycle to the room by the refrigerator is (in $J$)

$A$ refrigerator is to maintain eatables kept inside at $9^{\circ} C$. If room temperature is $36^{\circ} C$,calculate the coefficient of performance.

$A$ refrigerator with a coefficient of performance of $1/3$ releases $200 \ J$ of heat. What is the work done on the working substance in Joules?

Vedclass Test Series

Exam Paper Generator

Online Exam Module