A carrier wave of peak voltage 12 , V is used | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The modulation index $\mu$ is defined as the ratio of the peak voltage of the modulating signal $(A_m)$ to the peak voltage of the carrier wave $(

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(B) The modulation index $\mu$ is defined as the ratio of the peak voltage of the modulating signal $(A_m)$ to the peak voltage of the carrier wave $(A_c)$.$\mu = \frac{A_m}{A_c}$Given,$\mu = 75 \% = 0.75$ and $A_c = 12 \, V$.Substituting these values into the formula:$0.75 = \frac{A_m}{12}$$A_m = 0.75 	imes 12$$A_m = 9 \, V$.Therefore,the peak voltage of the modulating signal should be $9 \, V$.

$A$ carrier wave of peak voltage $12 \, V$ is used to transmit a message signal. What should be the peak voltage of the modulating signal in order to have a modulation index of $75 \%$? ...... $V$

Similar Questions

In amplitude modulation,

Basically,the product modulator is

Communication on ground is through electromagnetic waves of wavelength

In satellite communication,the uplink frequency band used is

An amplitude modulated wave is represented by $V_{AM} = 10[1 + 0.4 \cos(2 \pi \times 10^4 t)] \cos(2 \pi \times 10^7 t) \text{ V}$. The total bandwidth of the amplitude modulated wave is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module