A charged body has an electric flux phi assoc | vedclass

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(B) According to Gauss's Law,the total electric flux $\phi$ through any closed surface is equal to the net charge enclosed by the surface divided by t

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Equal to $\phi$

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(B) According to Gauss's Law,the total electric flux $\phi$ through any closed surface is equal to the net charge enclosed by the surface divided by the permittivity of free space,$\epsilon_0$,i.e.,$\phi = \frac{q_{enclosed}}{\epsilon_0}$.When a charged body is placed inside a metallic container,the net charge enclosed by a Gaussian surface surrounding the entire container remains the same as the charge on the body itself (due to electrostatic induction,equal and opposite charges are induced on the inner and outer surfaces of the metallic container,keeping the net charge enclosed by the outer Gaussian surface equal to the original charge $q$).Since the net charge enclosed remains the same,the total electric flux $\phi$ passing through the Gaussian surface outside the container remains equal to $\phi$.

$A$ charged body has an electric flux $\phi$ associated with it. The body is now placed inside a metallic container. The flux $\phi$ outside the container will be

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