A circular road runs around a circular garden | vedclass

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(B) Let the radius of the outer circle be $R$ and the radius of the inner circle be $r$.The width of the road is given by $(R - r)$.The circumference

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) Let the radius of the outer circle be $R$ and the radius of the inner circle be $r$.The width of the road is given by $(R - r)$.The circumference of the outer circle is $2 \pi R$ and the circumference of the inner circle is $2 \pi r$.Given that the difference between the circumferences is $44\, m$:$2 \pi R - 2 \pi r = 44$$2 \pi (R - r) = 44$$R - r = \frac{44}{2 \pi}$$R - r = \frac{44}{2 	imes (22/7)}$$R - r = \frac{44 	imes 7}{44} = 7\, m$.Thus,the width of the road is $7\, m$.

$A$ circular road runs around a circular garden. If the difference between the circumference of the outer circle and the inner circle is $44\, m$,then find the width of the road in $m$.

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