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(B) The maximum torque $	au_{\max}$ on a current-carrying coil in a magnetic field is given by the formula: $	au_{\max} = N I A B$,where $N$ is the

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Inversely proportional to $N$

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(B) The maximum torque $	au_{\max}$ on a current-carrying coil in a magnetic field is given by the formula: $	au_{\max} = N I A B$,where $N$ is the number of turns,$I$ is the current,$A$ is the area of the coil,and $B$ is the magnetic field strength.For a wire of length $L$ formed into a circular coil of $N$ turns,the circumference of one turn is $2\pi r = L/N$,so the radius $r = L/(2\pi N)$.The area of the coil is $A = \pi r^2 = \pi (L / (2\pi N))^2 = L^2 / (4\pi N^2)$.Substituting $A$ into the torque equation: $	au_{\max} = N I B (L^2 / (4\pi N^2)) = (I B L^2) / (4\pi N)$.Thus,$	au_{\max} \propto 1/N$. Therefore,the maximum torque is inversely proportional to $N$.

$A$ circular coil having $N$ turns is made from a wire of length $L$ meters. If a current $I$ amperes is passed through it and it is placed in a magnetic field of $B$ Tesla,the maximum torque on it is:

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