A circular coil of wire carries a current. PQ | vedclass

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(D) The current in the circular coil flows in a counter-clockwise direction. According to the right-hand thumb rule,the magnetic field produced by the

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At right angles to $PQ$,towards the left

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(D) The current in the circular coil flows in a counter-clockwise direction. According to the right-hand thumb rule,the magnetic field produced by the circular coil at the position of the wire $PQ$ is directed out of the plane of the paper.The wire $PQ$ carries a current flowing from $P$ to $Q$ (downwards). Using Fleming's left-hand rule or the vector cross product formula $\vec{F} = I(\vec{l} 	imes \vec{B})$:$1$. The current direction $\vec{l}$ is downwards.$2$. The magnetic field $\vec{B}$ is directed out of the plane.$3$. The cross product $\vec{l} 	imes \vec{B}$ points towards the left.Therefore,the force acting on the wire $PQ$ is perpendicular to $PQ$ and directed towards the left.

$A$ circular coil of wire carries a current. $PQ$ is a part of a very long wire carrying a current and passing close to the circular coil. If the directions of currents are those shown in the figure,what is the direction of the force acting on $PQ$?

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