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(B) The magnetic field $B$ at the centre of a circular loop is given by the formula: $B = \frac{\mu_0 I}{2r}$.Given values are: current $I = 2.0\,A$,r

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$8.0 	imes 10^{-5}\,Wb/m^2$

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(B) The magnetic field $B$ at the centre of a circular loop is given by the formula: $B = \frac{\mu_0 I}{2r}$.Given values are: current $I = 2.0\,A$,radius $r = 0.0157\,m$,and permeability $\mu_0 = 4\pi 	imes 10^{-7}\,T\cdot m/A$.Substituting these values into the formula:$B = \frac{(4\pi 	imes 10^{-7}) 	imes 2.0}{2 	imes 0.0157}$Since $\pi \approx 3.14$,we have $0.0157 = \frac{3.14}{200} = \frac{\pi}{200}$.$B = \frac{4\pi 	imes 10^{-7} 	imes 2}{2 	imes (\pi / 200)}$$B = 4 	imes 10^{-7} 	imes 2 	imes 100 = 8 	imes 10^{-5}\,Wb/m^2$.

$A$ circular loop of radius $0.0157\,m$ carries a current of $2.0\,A$. The magnetic field at the centre of the loop is $(\mu_0 = 4\pi \times 10^{-7}\,T\cdot m/A)$.

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