A colour blind man marries a woman with norma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) colour blind man has the genotype $X^cY$,and a normal woman has the genotype $XX$.When they marry,the offspring are: $X^cX$ (carrier daughter) and

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(B) colour blind man has the genotype $X^cY$,and a normal woman has the genotype $XX$.When they marry,the offspring are: $X^cX$ (carrier daughter) and $XY$ (normal son).All daughters are carriers $(X^cX)$ and all sons are normal $(XY)$.When a carrier daughter $(X^cX)$ marries a normal man $(XY)$,the possible genotypes for their children are: $XX$ (normal daughter),$X^cX$ (carrier daughter),$XY$ (normal son),and $X^cY$ (colour blind son).The probability of having a colour blind son (the grandson of the original couple) is $1/4$ or $0.25$.

$A$ colour blind man marries a woman with normal sight who has no history of colour blindness in her family. What is the probability of their grandson being colour blind?

Similar Questions

The blackening of urine when exposed to air is a metabolic disorder in human beings. This is due to the presence of:

The disease 'Haemophilia' is caused due to the lack of:

In pedigree analysis,the square,blackened,and horizontal lines represent:

$A$ woman with normal vision marries a man with normal vision and they have a color-blind son. What is the genotype of the mother?

The daughter born to a haemophilic father and a normal mother could be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module