A complex compound which can show optical iso | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Optical isomerism requires the absence of a plane of symmetry or center of inversion in the complex. This is typically observed in chiral com

Vedclass · Accepted Answer

$[Cr(ox)_3]^{3-}$

Vedclass · Answer

(C) $1$. Optical isomerism requires the absence of a plane of symmetry or center of inversion in the complex. This is typically observed in chiral complexes.$2$. Geometrical isomerism is observed in complexes that can form $cis$ and $trans$ isomers.$3$. $[Co(en)_2Cl_2]^+$ shows both geometrical ($cis$ and $trans$) and optical isomerism (for the $cis$ form).$4$. $[Co(NH_3)_5Cl]^{2+}$ does not show either type of isomerism.$5$. $[Cr(ox)_3]^{3-}$ is a tris-chelated complex of the type $[M(AA)_3]$. It does not have geometrical isomers because all donor atoms are identical,but it exists as a pair of enantiomers (optical isomers).$6$. $[Pt(NH_3)_2Cl_2]$ is a square planar complex that shows geometrical isomerism ($cis$ and $trans$) but cannot show optical isomerism due to the presence of a plane of symmetry in the square planar geometry.$7$. Therefore,$[Cr(ox)_3]^{3-}$ is the correct answer.

$A$ complex compound which can show optical isomerism but not geometrical isomerism is:

Similar Questions

Which of the following has the largest number of isomers?

Which of the following inner orbital complexes exhibits both geometrical and optical isomerism?

$[Co(NH_3)_4(NO_2)_2]Cl$ exhibits

Spin only magnetic moment of $[MnBr_{6}]^{4-}$ is $..... \ B.M.$ (round off to the closest integer)

How many geometrical isomers are possible for the square planar complex $[Pt(NO_2)(Py)(NH_3)(NO_2)]$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module