A complex current wave is given by i = 5 + 5 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given current wave is $i = 5 + 5 \sin(100 \omega t)$.To find the average value over one time period $T$,we use the formula $\langle i \rangle

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) The given current wave is $i = 5 + 5 \sin(100 \omega t)$.To find the average value over one time period $T$,we use the formula $\langle i angle = \frac{1}{T} \int_{0}^{T} i \, dt$.Substituting the expression for $i$:$\langle i angle = \frac{1}{T} \int_{0}^{T} (5 + 5 \sin(100 \omega t)) \, dt$.This can be split into two parts:$\langle i angle = \frac{1}{T} \int_{0}^{T} 5 \, dt + \frac{1}{T} \int_{0}^{T} 5 \sin(100 \omega t) \, dt$.The average value of a sine function over one complete cycle is $0$,i.e.,$\langle \sin(100 \omega t) angle = 0$.Therefore,$\langle i angle = 5 + 0 = 5 	ext{ A}$.

$A$ complex current wave is given by $i = 5 + 5 \sin(100 \omega t) \text{ A}$. Its average value over one time period is given as......$\text{A}$

Similar Questions

What are $DC$ signals and $AC$ signals? Why do we prefer an $AC$ signal?

The average value of the potential difference $V$ shown in the figure is:

An $ac$ generator produces an output voltage $E = 170 \sin(377t) \text{ volts}$,where $t$ is in seconds. The frequency of the $ac$ voltage is......$Hz$.

The phase difference between the voltage and the current in an $AC$ circuit is $\pi / 4$. If the frequency is $50 \ Hz$,then this phase difference will be equivalent to a time of:

The mean value of current for half cycle for a current variation shown by the graph is

Vedclass Test Series

Exam Paper Generator

Online Exam Module