$A$ compound $X$ is formed by the reaction of a carboxylic acid $C_{2}H_{4}O_{2}$ and an alcohol in the presence of a few drops of $H_{2}SO_{4}$. The alcohol,upon oxidation with alkaline $KMnO_{4}$ followed by acidification,gives the same carboxylic acid as used in this reaction. Give the names and structures of $(a)$ carboxylic acid,$(b)$ alcohol,and $(c)$ the compound $X$. Also,write the chemical reaction.
(A) The carboxylic acid is ethanoic acid $(CH_{3}COOH)$.
$(b)$ The alcohol is ethanol $(C_{2}H_{5}OH)$.
$(c)$ The compound $X$ is ethyl ethanoate $(CH_{3}COOC_{2}H_{5})$.
The reaction is an esterification reaction:
$CH_{3}COOH + C_{2}H_{5}OH \xrightarrow{H_{2}SO_{4}} CH_{3}COOC_{2}H_{5} + H_{2}O$
$(b)$ The alcohol is ethanol $(C_{2}H_{5}OH)$.
$(c)$ The compound $X$ is ethyl ethanoate $(CH_{3}COOC_{2}H_{5})$.
The reaction is an esterification reaction:
$CH_{3}COOH + C_{2}H_{5}OH \xrightarrow{H_{2}SO_{4}} CH_{3}COOC_{2}H_{5} + H_{2}O$
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