A compound X with molecular formula C_3H_8O c | vedclass

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Question

(A) The molecular formula $C_3H_8O$ corresponds to either a primary alcohol $(CH_3CH_2CH_2OH)$,a secondary alcohol $(CH_3CH(OH)CH_3)$,or an ether $(CH

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Primary alcohol

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(A) The molecular formula $C_3H_8O$ corresponds to either a primary alcohol $(CH_3CH_2CH_2OH)$,a secondary alcohol $(CH_3CH(OH)CH_3)$,or an ether $(CH_3OCH_2CH_3)$.Oxidation of a primary alcohol $(R-CH_2OH)$ yields an aldehyde $(R-CHO)$ and subsequently a carboxylic acid $(R-COOH)$.The molecular formula $C_3H_6O_2$ corresponds to propanoic acid $(CH_3CH_2COOH)$,which is a carboxylic acid.Since primary alcohols are the only alcohols that can be oxidized to carboxylic acids with the same number of carbon atoms,$X$ must be a primary alcohol $(CH_3CH_2CH_2OH)$.

Column-$I$ (Molecules)	Column-$II$ (Number of lone pairs on central atom)
$A$. $NH_3$	$1$. Two
$B$. $H_2O$	$2$. Three
$C$. $XeF_2$	$3$. Zero
$D$. $CH_4$	$4$. Four
	$5$. One

$A$ compound $X$ with molecular formula $C_3H_8O$ can be oxidised to a compound $Y$ with the molecular formula $C_3H_6O_2$. $X$ is most likely to be

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