A compound having molecular formula C_3H_6O,o | vedclass

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(C) The molecular formula $C_3H_6O$ corresponds to propanal $(CH_3CH_2CHO)$ or acetone $(CH_3COCH_3)$.Since the product $P$ shows stereoisomerism (geo

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(C) The molecular formula $C_3H_6O$ corresponds to propanal $(CH_3CH_2CHO)$ or acetone $(CH_3COCH_3)$.Since the product $P$ shows stereoisomerism (geometrical isomerism),the starting carbonyl compound must be propanal.Acetone semicarbazone $(CH_3C(NNHCONH_2)CH_3)$ does not show stereoisomerism because the two methyl groups on the carbon are identical.Propanal reacts with semicarbazide $(NH_2NHCONH_2)$ to form propanal semicarbazone $(CH_3CH_2CH=NNHCONH_2)$.This compound $P$ $(CH_3CH_2CH=NNHCONH_2)$ undergoes Wolff-Kishner reduction with $KOH$ / ethylene glycol to form propane.Thus,the correct structure for $P$ is $CH_3CH_2CH=NNHCONH_2$.

$A$ compound having molecular formula $C_3H_6O$,on reaction with $NH_2NHCONH_2$ produces mainly $P$ (which shows stereoisomerism). $P$ on reaction with $KOH$ / ethylene glycol,$\Delta$ produces propane. Identify $(P)$.

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