A compound with a molecular formula of C_6H_{ | vedclass

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(B) $n-$hexane $(CH_3-CH_2-CH_2-CH_2-CH_2-CH_3)$ has no tertiary carbon.$2-$methylpentane $(H_3C-CH_2-CH_2-CH(CH_3)-CH_3)$ has only one tertiary carbo

Vedclass · Accepted Answer

$2,3-$dimethylbutane

Vedclass · Answer

(B) $n-$hexane $(CH_3-CH_2-CH_2-CH_2-CH_2-CH_3)$ has no tertiary carbon.$2-$methylpentane $(H_3C-CH_2-CH_2-CH(CH_3)-CH_3)$ has only one tertiary carbon.$2,3-$dimethylbutane $(H_3C-CH(CH_3)-CH(CH_3)-CH_3)$ has two tertiary carbons.$2,2-$dimethylbutane $(H_3C-C(CH_3)_2-CH_2-CH_3)$ has no tertiary carbon.Therefore,the compound with two tertiary carbons is $2,3-$dimethylbutane.

$A$ compound with a molecular formula of $C_6H_{14}$ has two tertiary carbons. Its $IUPAC$ name is:

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