A capacitor of 2,mu F capacitance is charged | vedclass

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(A) The relationship between charge $(Q)$,capacitance $(C)$,and potential difference $(V)$ for a capacitor is given by the formula: $Q = CV$.Rearrangi

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(A) The relationship between charge $(Q)$,capacitance $(C)$,and potential difference $(V)$ for a capacitor is given by the formula: $Q = CV$.Rearranging this for potential difference,we get: $V = \frac{1}{C} Q$.This equation represents a straight line passing through the origin,where the slope of the line is $\frac{1}{C}$.Given $C = 2\,\mu F = 2 	imes 10^{-6}\,F$ and the maximum charge $Q = 5\,C$,the maximum potential difference is:$V = \frac{Q}{C} = \frac{5}{2 	imes 10^{-6}} = 2.5 	imes 10^{6}\,V$.Thus,the graph should be a straight line starting from $(0,0)$ and ending at $(5, 2.5 	imes 10^{6})$.Comparing this with the given options,graph $A$ correctly represents this linear relationship.

$A$ capacitor of $2\,\mu F$ capacitance is charged steadily from $0$ to $5\,C$. Which of the following graphs correctly represents the variation of potential difference $(V)$ across its plates with respect to the charge $(Q)$ on the capacitor?

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