A condenser of capacity 6 mu F is fully char | vedclass

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(D) The total energy stored in the capacitor is given by $U_{total} = \frac{1}{2} CV^2$.Given $C = 6 \ \mu F = 6 	imes 10^{-6} \ F$ and $V = 6 \ V$.$

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$0.6$

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(D) The total energy stored in the capacitor is given by $U_{total} = \frac{1}{2} CV^2$.Given $C = 6 \ \mu F = 6 	imes 10^{-6} \ F$ and $V = 6 \ V$.$U_{total} = \frac{1}{2} 	imes 6 	imes 10^{-6} 	imes (6)^2 = 108 	imes 10^{-6} \ J$.When the inductor is connected,the energy oscillates between the electric field of the capacitor and the magnetic field of the inductor.We are given that the energy in the magnetic field $(U_B)$ is one-third of the total energy:$U_B = \frac{1}{3} U_{total} = \frac{1}{3} 	imes \frac{1}{2} CV^2$.Since $U_B = \frac{1}{2} LI^2$,we have $\frac{1}{2} LI^2 = \frac{1}{3} 	imes \frac{1}{2} CV^2$.$I^2 = \frac{C V^2}{3L} = \frac{6 	imes 10^{-6} 	imes 36}{3 	imes 0.2 	imes 10^{-3}} = \frac{216 	imes 10^{-6}}{0.6 	imes 10^{-3}} = 360 	imes 10^{-3} = 0.36$.$I = \sqrt{0.36} = 0.6 \ A$.

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