A constant force F is applied in the horizont | vedclass

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(B) The system consists of three blocks of masses $M$,$m$,and $M'$ moving together with a common acceleration $a$ on a smooth surface.The total mass o

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$N > N'$

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(B) The system consists of three blocks of masses $M$,$m$,and $M'$ moving together with a common acceleration $a$ on a smooth surface.The total mass of the system is $M_{total} = M + m + M'$.The acceleration of the system is $a = \frac{F}{M + m + M'}$.To find the contact force $N$ between $M$ and $m$,we consider the free body diagram of the blocks $m$ and $M'$ together. The force $N$ pushes them forward:$N = (m + M') a = \frac{(m + M') F}{M + m + M'}$.To find the contact force $N'$ between $m$ and $M'$,we consider the free body diagram of block $M'$. The force $N'$ pushes it forward:$N' = M' a = \frac{M' F}{M + m + M'}$.Comparing $N$ and $N'$:Since $m > 0$,it follows that $(m + M') > M'$.Therefore,$N > N'$.

$A$ constant force $F$ is applied in the horizontal direction as shown in the figure. If the contact force between $M$ and $m$ is $N$ and the contact force between $m$ and $M'$ is $N'$,then:

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