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Question

(A) The relationship between torque $	au$ and the rate of change of angular momentum $L$ is given by the equation $	au = \frac{dL}{dt}$.Given the in

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$3A_0/4$

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(A) The relationship between torque $	au$ and the rate of change of angular momentum $L$ is given by the equation $	au = \frac{dL}{dt}$.Given the initial angular momentum $L_i = A_0$ and the final angular momentum $L_f = 4A_0$.The time interval $\Delta t = 4 \ s$.The change in angular momentum is $\Delta L = L_f - L_i = 4A_0 - A_0 = 3A_0$.Substituting these values into the formula,we get $	au = \frac{\Delta L}{\Delta t} = \frac{3A_0}{4} = 0.75A_0$.

$A$ constant torque acting on a uniform circular wheel changes its angular momentum from $A_0$ to $4A_0$ in $4 \ s$. The magnitude of this torque is

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