A convex mirror of focal length f forms an im | vedclass

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(A) For a convex mirror,the magnification $m$ is given by $m = +\frac{1}{n}$.Using the magnification formula $m = -\frac{v}{u}$,we have $\frac{1}{n} =

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$(n - 1)f$

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(A) For a convex mirror,the magnification $m$ is given by $m = +\frac{1}{n}$.Using the magnification formula $m = -\frac{v}{u}$,we have $\frac{1}{n} = -\frac{v}{u}$,which implies $v = -\frac{u}{n}$.According to the mirror formula,$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Substituting the value of $v$,we get $\frac{1}{f} = \frac{1}{-u/n} + \frac{1}{u} = -\frac{n}{u} + \frac{1}{u} = \frac{1 - n}{u}$.Therefore,$u = f(1 - n) = -(n - 1)f$.The distance of the object from the mirror is the magnitude of $u$,which is $(n - 1)f$.

$A$ convex mirror of focal length $f$ forms an image which is $1/n$ times the object. The distance of the object from the mirror is

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