A copper rod of cross-sectional area A carrie | vedclass

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(C) The volume charge density $\rho$ is defined as the total charge $q$ per unit volume $V$. For a rod of length $d$ and cross-sectional area $A$,the

Vedclass · Accepted Answer

$\frac{\rho dA}{I}$

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(C) The volume charge density $\rho$ is defined as the total charge $q$ per unit volume $V$. For a rod of length $d$ and cross-sectional area $A$,the volume is $V = A d$.Thus,$\rho = \frac{q}{V} = \frac{q}{A d}$,which implies $q = \rho A d$.Since current $I$ is defined as the rate of flow of charge,$I = \frac{q}{t}$,where $t$ is the time taken for the charge $q$ to pass through a cross-section.Rearranging for time $t$,we get $t = \frac{q}{I}$.Substituting the expression for $q$,we get $t = \frac{\rho A d}{I}$.

$A$ copper rod of cross-sectional area $A$ carries a uniform current $I$ through it. At temperature $T$,if the volume charge density of the rod is $\rho$,how long will the charges take to travel a distance $d$?

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