A cricketer catches a ball of mass 150; g in | vedclass

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(B) Given:Mass of the ball,$m = 150\; g = 0.15\; kg$Initial velocity,$u = 20\; m/s$Final velocity,$v = 0\; m/s$ (since the ball is caught)Time taken,$

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$30$

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(B) Given:Mass of the ball,$m = 150\; g = 0.15\; kg$Initial velocity,$u = 20\; m/s$Final velocity,$v = 0\; m/s$ (since the ball is caught)Time taken,$\Delta t = 0.1\; s$According to Newton's Second Law of Motion,the force $F$ is given by the rate of change of momentum:$F = \frac{\Delta p}{\Delta t} = \frac{m(v - u)}{\Delta t}$Substituting the values:$F = \frac{0.15 	imes (0 - 20)}{0.1} = \frac{0.15 	imes (-20)}{0.1} = \frac{-3}{0.1} = -30\; N$The magnitude of the force experienced by the cricketer is $30\; N$.

$A$ cricketer catches a ball of mass $150\; g$ in $0.1\; s$ moving with a speed of $20\; m/s$. The force experienced by the cricketer is ..... $N$.

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