(C) Let the average of $9$ innings be $x$. Total runs scored in $9$ innings $= 9x$. In the $10^{th}$ innings,he scored $100$ runs,so the new total run

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(C) Let the average of $9$ innings be $x$. Total runs scored in $9$ innings $= 9x$. In the $10^{th}$ innings,he scored $100$ runs,so the new total runs $= 9x + 100$. The new average after $10$ innings is $x + 8$. According to the problem: $\frac{9x + 100}{10} = x + 8$ $9x + 100 = 10(x + 8)$ $9x + 100 = 10x + 80$ $10x - 9x = 100 - 80$ $x = 20$. The average after $10$ innings $= x + 8 = 20 + 8 = 28$.

Competitive Quantitative Aptitude Average Average

Medium

$A$ cricketer scored some runs in his continuous $9$ innings. He scored $100$ runs in his $10^{th}$ innings and this increased his average by $8$ runs. What was the average of his runs at the end of $10^{th}$ innings?

A
$20$
B
$24$
C
$28$
D
$32$

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$A$ cricketer scored some runs in his continuous $9$ innings. He scored $100$ runs in his $10^{th}$ innings and this increased his average by $8$ runs. What was the average of his runs at the end of $10^{th}$ innings?

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The average of ten numbers is calculated. If each number is increased by $12 \%$,then the average

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