A cubical box has each edge 10, cm and anothe | vedclass

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(D) Total surface area of the cubical box $= 6 	imes (	ext{edge})^2 = 6 	imes (10\, cm)^2 = 600\, cm^2$.Total surface area of the cuboidal box $= 2

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$10$

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(D) Total surface area of the cubical box $= 6 	imes (	ext{edge})^2 = 6 	imes (10\, cm)^2 = 600\, cm^2$.Total surface area of the cuboidal box $= 2(lh + bh + lb) = 2(12.5 	imes 8 + 10 	imes 8 + 12.5 	imes 10) = 2(100 + 80 + 125) = 2(305) = 610\, cm^2$.Comparing the two, the total surface area of the cubical box $(600\, cm^2)$ is smaller than that of the cuboidal box $(610\, cm^2)$.The difference in surface area $= 610\, cm^2 - 600\, cm^2 = 10\, cm^2$.Thus, the cubical box has a smaller total surface area by $10\, cm^2$.

$A$ cubical box has each edge $10\, cm$ and another cuboidal box is $12.5\, cm$ long, $10\, cm$ wide and $8\, cm$ high. Which box has the smaller total surface area and by how much (in $ cm^2$)?

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