A cuboidal water tank is 2, m long,1, m wide, | vedclass

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(D) Given: Length $(l) = 2\, m = 200\, cm$,breadth $(b) = 1\, m = 100\, cm$,and height $(h) = 80\, cm$.The tank has five surfaces to be covered: two s

Vedclass · Accepted Answer

$170$

Vedclass · Answer

(D) Given: Length $(l) = 2\, m = 200\, cm$,breadth $(b) = 1\, m = 100\, cm$,and height $(h) = 80\, cm$.The tank has five surfaces to be covered: two sides of $(l 	imes h)$,two sides of $(b 	imes h)$,and one top surface of $(l 	imes b)$.Area of one square tile $= 20\, cm 	imes 20\, cm = 400\, cm^2$.$1$. Tiles for two surfaces of $(l 	imes h) = 2 	imes \frac{200 	imes 80}{400} = 2 	imes \frac{16000}{400} = 2 	imes 40 = 80$.$2$. Tiles for two surfaces of $(b 	imes h) = 2 	imes \frac{100 	imes 80}{400} = 2 	imes \frac{8000}{400} = 2 	imes 20 = 40$.$3$. Tiles for the top surface of $(l 	imes b) = \frac{200 	imes 100}{400} = \frac{20000}{400} = 50$.Total number of tiles $= 80 + 40 + 50 = 170$.

$A$ cuboidal water tank is $2\, m$ long,$1\, m$ wide,and $80\, cm$ deep (height). Its remaining five surfaces,excluding the base,are covered with square tiles of size $20\, cm \times 20\, cm$. Find the number of tiles required.

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