A current-carrying long solenoid is placed on | vedclass

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(D) The magnetic field inside a long current-carrying solenoid is directed along its axis. Since the proton is moving along the axis of the solenoid,i

Vedclass · Accepted Answer

Move along the same path with no change in velocity

Vedclass · Answer

(D) The magnetic field inside a long current-carrying solenoid is directed along its axis. Since the proton is moving along the axis of the solenoid,its velocity vector $v$ is parallel to the magnetic field vector $B$. The magnetic force $F$ on a charged particle is given by the Lorentz force formula: $F = q(v 	imes B)$. Since $v$ and $B$ are parallel,the angle $	heta$ between them is $0^\circ$ or $180^\circ$. Therefore,the magnetic force $F = qvB \sin(	heta) = qvB \sin(0^\circ) = 0$. As there is no magnetic force acting on the proton,it will continue to move along the same path with no change in its velocity.

$A$ current-carrying long solenoid is placed on the ground with its axis vertical. $A$ proton is falling along the axis of the solenoid with a velocity $v$. When the proton enters into the solenoid,it will

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