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(C) The torque acting on a current-carrying loop in a magnetic field is given by $\vec{	au} = \vec{M} 	imes \vec{B}$,where $\vec{M}$ is the magnetic

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$90^\circ$ to the direction of the field

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(C) The torque acting on a current-carrying loop in a magnetic field is given by $\vec{	au} = \vec{M} 	imes \vec{B}$,where $\vec{M}$ is the magnetic dipole moment and $\vec{B}$ is the magnetic field.For the loop to be in equilibrium,the net torque must be zero,which implies $\vec{	au} = 0$.This occurs when the angle between $\vec{M}$ and $\vec{B}$ is $0^\circ$ or $180^\circ$.Since $\vec{M}$ is always perpendicular to the plane of the loop,for $\vec{M}$ to be parallel to $\vec{B}$,the plane of the loop must be perpendicular to the magnetic field $\vec{B}$.Therefore,the plane of the loop is inclined at $90^\circ$ to the direction of the magnetic field.

$A$ current-carrying loop is free to turn in a uniform magnetic field. The loop will come into equilibrium when its plane is inclined at

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