A current of 2, mA was passed through an unkn | vedclass

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Question

(A) Given: Current $I = 2\, mA = 2 	imes 10^{-3}\, A$,Power $P = 4.4\, W$.Using the formula $P = I^2 R$,we find the resistance $R$:$R = \frac{P}{I^2}

Vedclass · Accepted Answer

$11 	imes 10^{-5}\, W$

Vedclass · Answer

(A) Given: Current $I = 2\, mA = 2 	imes 10^{-3}\, A$,Power $P = 4.4\, W$.Using the formula $P = I^2 R$,we find the resistance $R$:$R = \frac{P}{I^2} = \frac{4.4}{(2 	imes 10^{-3})^2} = \frac{4.4}{4 	imes 10^{-6}} = 1.1 	imes 10^6\, \Omega$.Now,when a voltage $V = 11\, V$ is applied across this resistor,the new power $P'$ is given by:$P' = \frac{V^2}{R} = \frac{11^2}{1.1 	imes 10^6} = \frac{121}{1.1 	imes 10^6} = 110 	imes 10^{-6}\, W = 11 	imes 10^{-5}\, W$.

$A$ current of $2\, mA$ was passed through an unknown resistor which dissipated a power of $4.4\, W$. The dissipated power when an ideal power supply of $11\, V$ is connected across it is:

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