A current of 10 ,A is maintained in a conduct | vedclass

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Question

(A) The relationship between current $I$ and drift velocity $V_d$ is given by the formula: $I = n e A V_d$.Here,$I = 10 \,A$,$n = 9 	imes 10^{28} \,m

Vedclass · Accepted Answer

$6.94 	imes 10^{-6}$

Vedclass · Answer

(A) The relationship between current $I$ and drift velocity $V_d$ is given by the formula: $I = n e A V_d$.Here,$I = 10 \,A$,$n = 9 	imes 10^{28} \,m^{-3}$,$e = 1.6 	imes 10^{-19} \,C$,and $A = 1 \,cm^2 = 10^{-4} \,m^2$.Substituting the values into the equation:$10 = (9 	imes 10^{28}) 	imes (1.6 	imes 10^{-19}) 	imes (10^{-4}) 	imes V_d$.$10 = (9 	imes 1.6 	imes 10^{28-19-4}) 	imes V_d$.$10 = (14.4 	imes 10^5) 	imes V_d$.$V_d = \frac{10}{14.4 	imes 10^5} = \frac{1}{1.44} 	imes 10^{-5} \approx 0.6944 	imes 10^{-5} = 6.94 	imes 10^{-6} \,m/s$.

$A$ current of $10 \,A$ is maintained in a conductor of cross-section $1 \,cm^2$. If the number density of free electrons is $9 \times 10^{28} \,m^{-3}$,the drift velocity of free electrons is .......... $m/s$.

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