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(D) The magnetic field $B$ produced by a current-carrying wire at a point is given by the Biot-Savart Law.According to the Biot-Savart Law,the magneti

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(D) The magnetic field $B$ produced by a current-carrying wire at a point is given by the Biot-Savart Law.According to the Biot-Savart Law,the magnetic field $d\vec{B}$ due to a current element $Id\vec{l}$ at a position vector $\vec{r}$ is given by $d\vec{B} = \frac{\mu_0}{4\pi} \frac{I(d\vec{l} 	imes \vec{r})}{r^3}$.For any point lying on the axis of the straight wire,the current element $Id\vec{l}$ and the position vector $\vec{r}$ are collinear (i.e.,the angle between them is $0^\circ$ or $180^\circ$).Since the cross product of collinear vectors is zero $(d\vec{l} 	imes \vec{r} = 0)$,the magnetic field at any point on the axis of the wire is zero.

$A$ current of $I$ $A$ is passed through a straight wire of length $2.0$ $m$. The magnetic field at a point in air at a distance of $3$ $m$ from either end of the wire and lying on the axis of the wire will be:

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