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Question

(C) Let the distance between the two places be $x$.Total distance covered $= x + x = 2x$.Time taken to go $= \frac{x}{u}$.Time taken to return $= \fra

Vedclass · Accepted Answer

$\frac{1}{\frac{1}{2}(\frac{1}{u}+\frac{1}{v})}$

Vedclass · Answer

(C) Let the distance between the two places be $x$.Total distance covered $= x + x = 2x$.Time taken to go $= \frac{x}{u}$.Time taken to return $= \frac{x}{v}$.Total time taken $= \frac{x}{u} + \frac{x}{v} = x(\frac{1}{u} + \frac{1}{v})$.Average speed $= \frac{	ext{Total distance}}{	ext{Total time}} = \frac{2x}{x(\frac{1}{u} + \frac{1}{v})} = \frac{2}{\frac{1}{u} + \frac{1}{v}}$.This can be rewritten as $\frac{1}{\frac{1}{2}(\frac{1}{u} + \frac{1}{v})}$.

$A$ cyclist goes from one place to another and returns by the same route. He pedals his way uniformly with speed $u$ while going and with speed $v$ while returning. The average speed of his journey is

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