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(C) The radius of the cylinder is equal to the radius of both the hemispheres,$r = 7 \, cm$.The height of the cylinder is calculated by subtracting th

Vedclass · Accepted Answer

$1496$

Vedclass · Answer

(C) The radius of the cylinder is equal to the radius of both the hemispheres,$r = 7 \, cm$.The height of the cylinder is calculated by subtracting the radii of the two hemispheres from the total height of the article:$h = 34 \, cm - (2 	imes 7 \, cm) = 34 - 14 = 20 \, cm$.The total surface area $(TSA)$ of the combined article is the sum of the curved surface area $(CSA)$ of the cylinder and the curved surface areas of the two hemispheres:$TSA = CSA_{	ext{cylinder}} + 2 	imes CSA_{	ext{hemisphere}}$$TSA = 2 \pi r h + 2 	imes (2 \pi r^2)$$TSA = 2 \pi r (h + 2r)$Substituting the values:$TSA = 2 	imes \frac{22}{7} 	imes 7 	imes (20 + 2 	imes 7)$$TSA = 44 	imes (20 + 14)$$TSA = 44 	imes 34 = 1496 \, cm^2$.Thus,the total surface area of the given article is $1496 \, cm^2$.

$A$ cylinder is closed at both the ends by hemispheres. The radius of the cylinder is $7 \, cm$ and the total height of the article is $34 \, cm$. Find the total surface area of the article. (in $cm^2$)

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