A cylindrical bucket is 72, cm high and 28, c | vedclass

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(C) The radius of the cylindrical bucket is $r = \frac{28}{2} = 14\, cm$.The height of the bucket is $h = 72\, cm$.The volume of water in the bucket i

Vedclass · Accepted Answer

$24$

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(C) The radius of the cylindrical bucket is $r = \frac{28}{2} = 14\, cm$.The height of the bucket is $h = 72\, cm$.The volume of water in the bucket is given by $V = \pi r^2 h$.$V = \frac{22}{7} 	imes 14 	imes 14 	imes 72 = 22 	imes 2 	imes 14 	imes 72 = 44,352\, cm^3$.Let the height of the water level in the rectangular tank be $H$.The volume of water in the tank is $V = 	ext{length} 	imes 	ext{breadth} 	imes H = 66 	imes 28 	imes H$.Equating the volumes: $66 	imes 28 	imes H = 44,352$.$H = \frac{44,352}{66 	imes 28} = \frac{44,352}{1,848} = 24\, cm$.

$A$ cylindrical bucket is $72\, cm$ high and $28\, cm$ in diameter and is full of water. This water is emptied into a rectangular tank whose length and breadth are $66\, cm$ and $28\, cm$,respectively. What will be the height of the water level in the tank? (in $cm$)

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