A cylindrical tube open at both ends is made | vedclass

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(B) The tube is a hollow cylinder.Outer diameter $= 16 \, cm$, so outer radius $(R) = 16 / 2 = 8 \, cm$.Thickness of the iron sheet $= 2 \, cm$.Inner

Vedclass · Accepted Answer

$8800$

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(B) The tube is a hollow cylinder.Outer diameter $= 16 \, cm$, so outer radius $(R) = 16 / 2 = 8 \, cm$.Thickness of the iron sheet $= 2 \, cm$.Inner radius $(r) = R - 	ext{thickness} = 8 \, cm - 2 \, cm = 6 \, cm$.Length (height) of the cylinder $(h) = 100 \, cm$.The volume of iron used is the difference between the outer volume and the inner volume of the cylinder.Volume $= \pi (R^2 - r^2) h$Volume $= \frac{22}{7} 	imes (8^2 - 6^2) 	imes 100$Volume $= \frac{22}{7} 	imes (64 - 36) 	imes 100$Volume $= \frac{22}{7} 	imes 28 	imes 100$Volume $= 22 	imes 4 	imes 100 = 8800 \, cm^3$.

$A$ cylindrical tube open at both ends is made of an iron sheet which is $2 \, cm$ thick. If the outer diameter is $16 \, cm$ and its length is $100 \, cm$, find how many cubic centimeters of iron have been used in making the tube? (in $cm^3$)

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