A die is tossed thrice. If getting a four is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) This is a binomial distribution problem where $n = 3$ (number of trials).Success is defined as getting a $4$ on a die.The probability of success $

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) This is a binomial distribution problem where $n = 3$ (number of trials).Success is defined as getting a $4$ on a die.The probability of success $p = \frac{1}{6}$.The probability of failure $q = 1 - p = 1 - \frac{1}{6} = \frac{5}{6}$.Mean of binomial distribution is given by $\mu = np = 3 	imes \frac{1}{6} = \frac{1}{2}$.Variance of binomial distribution is given by $\sigma^2 = npq = 3 	imes \frac{1}{6} 	imes \frac{5}{6} = \frac{5}{12}$.Thus,the mean is $\frac{1}{2}$ and the variance is $\frac{5}{12}$.Since this pair is not present in options $A, B,$ or $C$,the correct option is $D$.

$A$ die is tossed thrice. If getting a four is considered a success,then the mean and variance of the probability distribution of the number of successes are

Similar Questions

$A$ person can kill a bird with a probability of $3/4$. He tries $5$ times. What is the probability that he may not kill the bird at all?

If a random variable $X$ follows the Binomial distribution $B(33, p)$ such that $3P(X=0) = P(X=1)$,then the value of $\frac{P(X=15)}{P(X=18)} - \frac{P(X=16)}{P(X=17)}$ is equal to

$A$ die is thrown three times. Getting a $3$ or a $6$ is considered success. Then the probability of at least two successes is

If the mean and variance of a binomial variable $X$ are $2.4$ and $1.44$ respectively,then the parameters $n$ and $p$ are respectively

$A$ multiple choice examination has $5$ questions. Each question has three alternative answers of which exactly one is correct. The probability that a student will get $4$ or more correct answers just by guessing is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module