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(C) In the vertical plane perpendicular to the magnetic meridian,the effective magnetic field acting on the needle is the vertical component of the Ea

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(C) In the vertical plane perpendicular to the magnetic meridian,the effective magnetic field acting on the needle is the vertical component of the Earth's magnetic field,$B_V$. The time period is given by $T_1 = 2\pi \sqrt{\frac{I}{MB_V}} = 2 	ext{ s}$.In the horizontal plane,the effective magnetic field acting on the needle is the horizontal component of the Earth's magnetic field,$B_H$. The time period is given by $T_2 = 2\pi \sqrt{\frac{I}{MB_H}} = 2 	ext{ s}$.Since $T_1 = T_2$,we have $B_V = B_H$.The angle of dip $\phi$ is defined by the relation $	an \phi = \frac{B_V}{B_H}$.Substituting $B_V = B_H$,we get $	an \phi = 1$,which implies $\phi = 45^o$.

$A$ dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. The time period of vibration is found to be $2$ seconds. The same needle is then allowed to vibrate in the horizontal plane and the time period is again found to be $2$ seconds. Then the angle of dip is.....$^o$

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